Re: Integration by substitution
- To: mathgroup at smc.vnet.net
- Subject: [mg29824] Re: [mg29800] Integration by substitution
- From: "J Rockmann" <mtheory at msn.com>
- Date: Thu, 12 Jul 2001 02:52:37 -0400 (EDT)
- References: <200107110025.UAA20901@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
----- Original Message -----
From: "G. A. Garrett" <ggarrett7 at netscape.net>
To: mathgroup at smc.vnet.net
Subject: [mg29824] [mg29800] Integration by substitution
> I was wondering if someone could explain to me why the first input
> below gives no answer while the second input does. It never crossed my
> mind the Mathematica wouldn't have seen the simple substitution of
> sp=s/a that produced an answer. I am running ver. 4.0 in a Windows
> environment. I am basically looking for a characteristic that I can be
> on the look out for in the future.
>
> Integrate[Sech[s/a]^2 Sech[(t - s)/a]^2, {s, -Infinity, Infinity}]
>
> Integrate[a Sech[sp]^2 Sech[(tp - sp)]^2, {sp, -Infinity, Infinity}]
>
> Gregory
> --Posted email rarely checked--
>
If I'm not mistaken, Mathematica will consider "sp" as a single variable as
it would "x". Therefore, the two statements are not equivalent to
Mathematica after any algebraic manipulation has been performed on your
naming of the variable "sp=sa".
I hope this helps,
Jonathan Rockmann
mtheory at msn.com
- References:
- Integration by substitution
- From: ggarrett7@netscape.net (G. A. Garrett)
- Integration by substitution