Re: Conditions

• To: mathgroup at smc.vnet.net
• Subject: [mg29246] Re: Conditions
• From: "Allan Hayes" <hay at haystack.demon.co.uk>
• Date: Fri, 8 Jun 2001 04:15:33 -0400 (EDT)
• References: <9fna8p\$bih\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Yannis,
We can create a function which carries out your instructions for each row
and map it over the rows of m.

m={{1,2,0,3,4},{1,2,3,4,5}};

If[FreeQ[#,0], Last[#], 0]&/@m

{0,5}

--
Allan
---------------------
Allan Hayes
Mathematica Training and Consulting
Leicester UK
www.haystack.demon.co.uk
hay at haystack.demon.co.uk
Voice: +44 (0)116 271 4198
Fax: +44 (0)870 164 0565

<Yannis.Paraskevopoulos at ubsw.com> wrote in message
news:9fna8p\$bih\$1 at smc.vnet.net...
> Hi again,
>
> I've been puzzled by the following problem which I  have to admit it's
> not complicated but yet...
>
> assume that we have a matrix m with dimensions (RxC) then create a
> vector v, which has value 0 when there is a zero at any point across
> m's row. Otherwise v's value would be equal to the last value of the
> corresponding m row.
>
>
> I tried for example:
>
>
> I initiated a vector v={a,b}. I had to that as
>
> Table[If[m[[i,j]]==0,v[[i]]=0,v[[i]]=g[[i,5]]],{i,2},{j,5}];
> v
>
> Out:= {1,1} when I expected {0,1}
>
>
> I also tried
>
>
> v:=0 /; g/.x_:>x==0
> v:=Table[g[[i,5]],{i,2}]
>
> with same results.
>
> Its obvious to me that I do something stupid but I can't figure it out.
> Any help would be very much appreciated.
>
> Best regards
>
>
> yannis
>
>
>
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```

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