Re: Replacing 1 to many in a list
- To: mathgroup at smc.vnet.net
- Subject: [mg29278] Re: Replacing 1 to many in a list
- From: "Stephen P Luttrell" <luttrell at signal.dra.hmg.gb>
- Date: Sat, 9 Jun 2001 03:09:06 -0400 (EDT)
- References: <9fq1sf$qdl$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
This does what you want:
vector = {6, 6, 5, 4, 4, 4, Null, 6, Null, 44, Null, 4, 4, 5};
pos = Position[vector, Null];
MapIndexed[(vector[[#[[1]]]] = x[#2[[1]]]) &, pos];
vector
--
Stephen P Luttrell
DERA Malvern, U.K.
"Chris Johnson" <cjohnson at shell.faradic.net> wrote in message
news:9fq1sf$qdl$1 at smc.vnet.net...
> I think this is probably simple, but I can't find a natural way to do it
> yet. I hope someone out there can help. I have a vector numbers with
> some Null's scattered throughout. The number and location of missing data
> varies. For example,
>
> vector = {6, 6, 5, 4, 4, 4, Null, 6, Null, 44, Null, 4, 4, 5}
>
> Position[vector, Null]
>
> {{7}, {9}, {11}}
>...