       Re: A New User

• To: mathgroup at smc.vnet.net
• Subject: [mg29334] Re: [mg29321] A New User
• From: Andrzej Kozlowski <andrzej at tuins.ac.jp>
• Date: Thu, 14 Jun 2001 02:27:15 -0400 (EDT)
• Sender: owner-wri-mathgroup at wolfram.com

```I think you must be a very new user. For a start Sqrt(3) in Mathematica is
not at all what you think it is. You won't get very far unless you learn the
correct syntax.

Also, since

In:=
Simplify[ (2+Sqrt)*(1+2*Sqrt)]

Out=
8 + 5 Sqrt

learning the correct syntax would go a long way towards solving your
problem.

--
Andrzej Kozlowski
Toyama International University
JAPAN

http://platon.c.u-tokyo.ac.jp/andrzej/
http://sigma.tuins.ac.jp/~andrzej/

on 01.6.13 4:10 PM, Jim-dars at jim-dars at mediaone.net wrote:

> Hi All,
>
> I have a problem of the form:
>
> (2+Sqrt(3))*(1+2*Sqrt(3))
>
> I would like Mathematica to present the solution in the form (8 +
> 5*Sqrt(3)).
>
> Of course, I realize I can calculate the two components.  However, since
> this situation occurs repeatedly in a problem I'm solving, it would be very
> convenient to have Mathematica display the answer directly.  In fact, if
> Mathematica could provide me with a=8 and b=5 that would be even better.
>
> My actual problem is of the form:
>
> (a+b*Sqrt(c))*(d+e*Sqrt(c))^k  = (f+g*Sqrt(c))
>
> where a,b,c,d, and e are positive integers.  c is not a perfect square, but
> may contain a square factor.
> k is an integer such that -infinity < k < infinity.   It is desired to find
> f and g.  (Actually, just g.)
>
> Best wishes, Jim
>
>
>

```

• Prev by Date: Re: Strange problems about my mathematica
• Next by Date: Re: Re: Strange problems about my mathematica
• Previous by thread: Re: A New User
• Next by thread: Re: A New User