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Re: A New User

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  • Subject: [mg29334] Re: [mg29321] A New User
  • From: Andrzej Kozlowski <andrzej at>
  • Date: Thu, 14 Jun 2001 02:27:15 -0400 (EDT)
  • Sender: owner-wri-mathgroup at

I think you must be a very new user. For a start Sqrt(3) in Mathematica is
not at all what you think it is. You won't get very far unless you learn the
correct syntax. 

Also, since 

Simplify[ (2+Sqrt[3])*(1+2*Sqrt[3])]

8 + 5 Sqrt[3]

learning the correct syntax would go a long way towards solving your

Andrzej Kozlowski
Toyama International University

on 01.6.13 4:10 PM, Jim-dars at jim-dars at wrote:

> Hi All,
> I have a problem of the form:
> (2+Sqrt(3))*(1+2*Sqrt(3))
> I would like Mathematica to present the solution in the form (8 +
> 5*Sqrt(3)).
> Of course, I realize I can calculate the two components.  However, since
> this situation occurs repeatedly in a problem I'm solving, it would be very
> convenient to have Mathematica display the answer directly.  In fact, if
> Mathematica could provide me with a=8 and b=5 that would be even better.
> My actual problem is of the form:
> (a+b*Sqrt(c))*(d+e*Sqrt(c))^k  = (f+g*Sqrt(c))
> where a,b,c,d, and e are positive integers.  c is not a perfect square, but
> may contain a square factor.
> k is an integer such that -infinity < k < infinity.   It is desired to find
> f and g.  (Actually, just g.)
> Best wishes, Jim

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