Re: A New User
- To: mathgroup at smc.vnet.net
- Subject: [mg29334] Re: [mg29321] A New User
- From: Andrzej Kozlowski <andrzej at tuins.ac.jp>
- Date: Thu, 14 Jun 2001 02:27:15 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
I think you must be a very new user. For a start Sqrt(3) in Mathematica is not at all what you think it is. You won't get very far unless you learn the correct syntax. Also, since In[8]:= Simplify[ (2+Sqrt[3])*(1+2*Sqrt[3])] Out[8]= 8 + 5 Sqrt[3] learning the correct syntax would go a long way towards solving your problem. -- Andrzej Kozlowski Toyama International University JAPAN http://platon.c.u-tokyo.ac.jp/andrzej/ http://sigma.tuins.ac.jp/~andrzej/ on 01.6.13 4:10 PM, Jim-dars at jim-dars at mediaone.net wrote: > Hi All, > > I have a problem of the form: > > (2+Sqrt(3))*(1+2*Sqrt(3)) > > I would like Mathematica to present the solution in the form (8 + > 5*Sqrt(3)). > > Of course, I realize I can calculate the two components. However, since > this situation occurs repeatedly in a problem I'm solving, it would be very > convenient to have Mathematica display the answer directly. In fact, if > Mathematica could provide me with a=8 and b=5 that would be even better. > > My actual problem is of the form: > > (a+b*Sqrt(c))*(d+e*Sqrt(c))^k = (f+g*Sqrt(c)) > > where a,b,c,d, and e are positive integers. c is not a perfect square, but > may contain a square factor. > k is an integer such that -infinity < k < infinity. It is desired to find > f and g. (Actually, just g.) > > Best wishes, Jim > > >