MathGroup Archive 2001

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Re:from Malta

  • To: mathgroup at smc.vnet.net
  • Subject: [mg27558] Re:from Malta
  • From: bghiggins at ucdavis.edu (Brian Higgins)
  • Date: Wed, 7 Mar 2001 04:07:55 -0500 (EST)
  • Organization: The Math Forum
  • References: <97l2tb$jf0@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

If you have a m by n matrix(A), then the fundamental theorem of linear
algebra relates the four subspaces associated with A:

Column space of A, nullspace of A,  the column space of transpose(A)
and nullspace of transpose(A):


Thus 

dim{column space of transpose(A) }+dim{nullspace of A}=n

dim{column space of A}+dim{nullspace of transpose(A)}=m

In mathematica the dimensions of the various subpaces can be found
using NullSpace, RowReduce

Thus dimension of nullspace is

 Length[NullSpace[A]]

Dimension of the column space of A is

Length[DeleteCases[RowReduce[A], {0, 0, 0, 0}]]

or

Last[Dimensions[A]] - Length[NullSpace[A]]


Hope this helps,

Brian


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