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Re: Question

  • To: mathgroup at smc.vnet.net
  • Subject: [mg28089] Re: Question
  • From: Matthias Hertel <wir95cgu at studserv.uni-leipzig.de>
  • Date: Fri, 30 Mar 2001 04:12:41 -0500 (EST)
  • References: <200103272035.PAA23800@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Per,

L1 = FoldList[Plus, 0, Range[4, 2, -1]]
L2 = FoldList[Plus, 0, Range[5, 2, -1]]
L3 = FoldList[Plus, 0, Range[6, 2, -1]]

or, in the template you gave, replace ? with

    Sum[k, {k, n - i + 2, n}]

In[1]:= n=6;
In[2]:= Table[Sum[k, {k, n - i + 2, n}], {i, 1, n, 1}]

Out[2]= {0, 6, 11, 15, 18, 20}

But to me, this looks much more obfuscated than the version using
FoldList.

Regards
Matthias

"Per Lundgren" <yesgoyes at ebox.tninet.se> writes:
> "Hello,
> I am looking for the formula to create the following sets L1, L2 and L3 of 
> numbers using 
> Sum or Table and following the principle
> Table[?,{i,1,n,1}]     n=4,5,6
> 
> Thanks in advance. Per Lundgren, Sweden
> yesgoyes at ebox.tninet.se
> :";
> 
> L1 = {0, 4, 7, 9}
> L2 = {0, 5, 9, 12, 14}
> L3 = {0, 6, 11, 15, 18, 20}


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