       Re: rewriting a fraction a/b==c/d + e/f

• To: mathgroup at smc.vnet.net
• Subject: [mg31019] Re: rewriting a fraction a/b==c/d + e/f
• From: "Alan Mason" <swt at austin.rr.com>
• Date: Tue, 2 Oct 2001 01:20:56 -0400 (EDT)
• References: <9p93dn\$oce\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Hello Okke.
All you need to do is use Apart[]; this gives partial fraction expansions.
In:=
1/((x-1)(x^2+x+1))

In:=
Apart[%]

Out=
\!\(1\/\(3\ \((\(-1\) + x)\)\) + \(\(-2\) - x\)\/\(3\ \((1 + x + x\^2)\)\)\)

"Okke" <kroosu at tref.nl> wrote in message news:9p93dn\$oce\$1 at smc.vnet.net...
> hello,
> i'm trying the mathematica demo by doing some basic mathematics.
> now i'm stuck at rewritting a fraction.
>
> 1/((x-1)(x^2+x+1)) to A/(x-1) + (Bx+C)/(x^2+x+1)
> or do i have to do that manualy?
> and can mathematica find  the values for A, B and C ?
> Solve[eqn1==eq2,{A}] doesnt solve the problem, and subsituting
> x with 1 doesnt either.
>
> tia,
> --
> Okke <kroosu at tref.nl>
>

```

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