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Re: Using % in ; separated commands

  • To: mathgroup at smc.vnet.net
  • Subject: [mg35897] Re: Using % in ; separated commands
  • From: "Robert Hunn" <rw_padding_hunn at worldnet.att.net>
  • Date: Wed, 7 Aug 2002 05:59:14 -0400 (EDT)
  • References: <ailj89$hq2$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Try
d = a /. Last[Solve[Sin[a] == 0.4717 * Sin[(Pi/3) - a], a]]
The variable d now contains only the last numerical value of solve and not
the replacement rule.

"Kaustubh Raghukumar" <kausmic at yahoo.com> wrote in message
news:ailj89$hq2$1 at smc.vnet.net...
> Hi,
> I have been using Mathematica for basic stuff so far
> and find myself lost on how to acheive the following:
>
> I need to extract the last numerical value of 'a' in
> Solve ( without the 'a ->'), so I can use it
> elsewhere, without having to type it in. Here is what
> I wrote
>
> Solve[Sin[a]==0.4717 * Sin[(Pi/3)-a],a]; Last[a /. %]
>
> The problem is that the value in '%' is not the output
> of Solve, but the whatever operation came before that!
> Any help on how to extract the last numerical from
> solve will be greatly appreciated.
>
> Thanks a lot,
> Kaustubh
>
>
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