RE: Using % in ; separated commands
- To: mathgroup at smc.vnet.net
- Subject: [mg35896] RE: [mg35889] Using % in ; separated commands
- From: "David Park" <djmp at earthlink.net>
- Date: Wed, 7 Aug 2002 05:59:13 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Kaustubh, If you put your second statement on a new line, using a carriage return, it will work; Solve[Sin[a] == 0.4717 * Sin[(Pi/3) - a], a]; Last[a /. %] Solve::"ifun": "Inverse functions are being used by \!\(Solve\), so some \ solutions may not be found." 0.319239 David Park djmp at earthlink.net http://home.earthlink.net/~djmp/ From: Kaustubh Raghukumar [mailto:kausmic at yahoo.com] To: mathgroup at smc.vnet.net Hi, I have been using Mathematica for basic stuff so far and find myself lost on how to acheive the following: I need to extract the last numerical value of 'a' in Solve ( without the 'a ->'), so I can use it elsewhere, without having to type it in. Here is what I wrote Solve[Sin[a]==0.4717 * Sin[(Pi/3)-a],a]; Last[a /. %] The problem is that the value in '%' is not the output of Solve, but the whatever operation came before that! Any help on how to extract the last numerical from solve will be greatly appreciated. Thanks a lot, Kaustubh __________________________________________________ Do You Yahoo!? Yahoo! Health - Feel better, live better http://health.yahoo.com