Re: Handling a list: Could you find a more elegant solution?
- To: mathgroup at smc.vnet.net
- Subject: [mg38246] Re: Handling a list: Could you find a more elegant solution?
- From: "Allan Hayes" <hay at haystack.demon.co.uk>
- Date: Tue, 10 Dec 2002 04:09:50 -0500 (EST)
- References: <asn36u$40k$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
> I have a list:
>
> list1 = {a, b, c, d, e};
>
> I want manipulate the list to obtain:
>
> (*Out[]:{(a + b)/2, (b + c)/2, (c + d)/2, (d + e)/2}*)
list1={a,b,c,d,e};
ListCorrelate[{1,1},list1]/2
{(a + b)/2, (b + c)/2, (c + d)/2, (d + e)/2}
--
Allan
---------------------
Allan Hayes
Mathematica Training and Consulting
Leicester UK
www.haystack.demon.co.uk
hay at haystack.demon.co.uk
Voice: +44 (0)116 271 4198
Fax: +44 (0)870 164 0565
<guillerm at usal.es> wrote in message news:asn36u$40k$1 at smc.vnet.net...
> I have a list:
>
> list1 = {a, b, c, d, e};
>
> I want manipulate the list to obtain:
>
> (*Out[]:{(a + b)/2, (b + c)/2, (c + d)/2, (d + e)/2}*)
>
> It can be done for this function
>
> f[data_List] := Drop[Plus @@ NestList[RotateRight, data,
> 1], 1]/2
>
> f[list1]
>
> but I am sure that some member of the group can find a more elegant
function. I
> will appreciate to know it.
>
> Thanks
>
> Guillermo Sanchez
>
>
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