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Re: polar curve

  • To: mathgroup at
  • Subject: [mg32348] Re: polar curve
  • From: "Borut L" <borut at>
  • Date: Wed, 16 Jan 2002 03:29:58 -0500 (EST)
  • References: <a20mh4$4h2$>
  • Sender: owner-wri-mathgroup at

Is this your homework assignment? Because it sounds like a homework

Anyway, I am cool enough to give you few tips:

x(t) = r(t) cos(t)
y(t) = r(t) sin(t)

Derivate x(t) on t and you get x'(t), set this to zero, and you get yourself
x0, y0 follows.
Draw the curve (PolarPlot[r(t)] or ParametricPlot[{x[t],y[t]}]) and figure
out the nature of the tangents at those points.

<TeKkEnXpErT at> wrote in message news:a20mh4$4h2$1 at
> A polar curve defined by the equation r = 4cos(theta) -pie/2<=theta<=pie/2
> Parametrize the curve by x(theta), y(theta). Find the points (x,y) on this
> curve at which x'(theta)=0. What can you say about the tangent at  these
> points?

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