Re: Taylor Series Expansions
- To: mathgroup at smc.vnet.net
- Subject: [mg32383] Re: Taylor Series Expansions
- From: <emueller at ybkim.mps.ohio-state.edu>
- Date: Thu, 17 Jan 2002 02:23:37 -0500 (EST)
- Organization: Ohio State University
- References: <a23g46$9mq$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Try introducing a "dummy parameter" to keep track of the order of the
expansion, such as:
Series[f[x,y] /. {x->a x,y->a y},{a,0,2}] //Normal /.a->1
Erich
On Wed, 16 Jan 2002, Joe Helfand wrote:
> Wow!
>
> I have definitely come to the right place. Thanks for all the
> responses. Using the Map built in function solved my problem (it still
> took a bit, so you can imagine what I was dealing with). Here is
> something else which I have wasted some time on not knowing as much
> about Mathematica as I should. It has to do with multi-variable Taylor
> series expansion. Mathematica has a built in Series function. But when
> you use this for multi-variable functions, it doesn't do quite what I'd
> expect. Let's say I have a function for two fariables, and I want to
> expand to 2nd order. When I use Series, it expands each varible to
> second order, but includes the cross terms, which I want to belong to a
> 4th order expansion. For example:
>
> In[1172]:=
> Normal[Series[Exp[x y], {x, 0, 2}, {y, 0, 2}]]
>
> Out[1172]=
> \!\(1 + x\ y + \(x\^2\ y\^2\)\/2\)
>
> But what I really want is just 1 + x y, where if I go to fourth order,
> then I'll take the x^2 y^2 / 2. I had to take some time to write some
> sloppy Taylor series expansion functions that did what I wanted. Is
> there a way to get around this problem or do you have any suggestions?
>
> Thanks Again,
> Joe
>
>
>
>