Re: AW: Q: Simplify with "much less" assumptions
- To: mathgroup at smc.vnet.net
- Subject: [mg35644] Re: AW: Q: Simplify with "much less" assumptions
- From: phbrf at t-online.de (Peter Breitfeld)
- Date: Wed, 24 Jul 2002 02:06:08 -0400 (EDT)
- References: <ahivod$gn6$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Matthias.Bode at oppenheim.de schrieb:
>
> Hello Heather,
>
> try:
>
> 1 + x^2 /. {x -> 0}
>
> It will give you the 1 you wish.
>
> Best regards,
> Matthias Bode.
>
If you only want to neglect powers with exponent greater 1 you may use
the rule
In[1]:=regel=x^(n_/;n>1)->0
then
In[2]:=1 + x + x^2 + x^3 + x^1.5 + x^(7/4) + x^0.5 + x^(3/4)/.regel
Out[2]=1+x+x^0.5+x^(3/4)
Gruß Peter
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Peter Breitfeld, Bad Saulgau, Germany Meinen GnuPG/PGP-5x Key gibts dort