Re: PolynomialQ ?
- To: mathgroup at smc.vnet.net
- Subject: [mg34911] Re: PolynomialQ ?
- From: lalu_bhatt at yahoo.com (Bhuvanesh)
- Date: Wed, 12 Jun 2002 02:16:00 -0400 (EDT)
- References: <ae4en8$9bc$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
"Juan" <erfa11 at hotmail.com> wrote:
> Hi,I tried to check is a polynomial have a variable, ussing the function
> PolynomialQ.
>
> In[1]:=p = x^3 - 2*x^2 + x - 1;
> In[2]:=PolynomialQ[p, x]
> Out[2]=True
> In[3]:=PolynomialQ[p, y]
> Out[3]=True
> In[4]:=PolynomialQ[p, z^2]
> Out[4]=True
> In[5]:=PolynomialQ[p, {u, v}]
> Out[5]=True
>
> What is the thing I am doing wrong?
The polynomial in x is a constant in y, in z^2, and in {u,v}, and is
therefore a polynomial in those variables as well. If you want no
other variables to be present, you might look into FreeQ:
http://documents.wolfram.com/v4/RefGuide/FreeQ.html
--
Bhuvanesh,
Wolfram Research.