Re: a + b = c + d where a^2 + b^2 = c^2 + d^2.
- To: mathgroup at smc.vnet.net
- Subject: [mg33555] Re: [mg33544] a + b = c + d where a^2 + b^2 = c^2 + d^2.
- From: Andrzej Kozlowski <andrzej at bekkoame.ne.jp>
- Date: Sun, 31 Mar 2002 04:09:02 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Why did you use SolveAlways? It's meant for a completely different
purpose (identities, not equations!). The best way is to use Reduce:
In[20]:=
eqns = {a + b == c + d, a^2 + b^2 == c^2 + d^2};
In[22]:=
Reduce[eqns,{a,b,c,d}]
Out[22]=
a==c&&b==d||a==d&&b==c
Andrzej Kozlowski
Toyama International University
JAPAN
http://platon.c.u-tokyo.ac.jp/andrzej/
On Friday, March 29, 2002, at 08:13 PM, TheSquaredBun wrote:
> Hi,
>
> I tried to find solutions for a + b = c + d where a^2 + b^2 = c^2 +
> d^2.
>
> I tried the following, but that gave no results:
> In[3]:=
> \!\(\(eqns = {a\ + \ b == c + d, a\^2 + b\^2 == c\^2 + d\^2};\)\)
>
> In[7]:=
> SolveAlways[eqns, {a, b, c, d}]
>
> Out[7]=
> {}
>
> Does anyone have an idea how to handle this problem with mathematica?
>
> Thanks in advance,
>
> Roderik,
> TheSquaredBun
>
> ----------------------------------------------
> Top 100 Nederland (gratis aanmelden, direct meer bezoekers)
> http://www.nl100.tk of
> http://www.topsitelists.com/bestsites/nl100/topsites.html
>
>
>
>