       Re: a + b = c + d where a^2 + b^2 = c^2 + d^2.

• To: mathgroup at smc.vnet.net
• Subject: [mg33555] Re: [mg33544] a + b = c + d where a^2 + b^2 = c^2 + d^2.
• From: Andrzej Kozlowski <andrzej at bekkoame.ne.jp>
• Date: Sun, 31 Mar 2002 04:09:02 -0500 (EST)
• Sender: owner-wri-mathgroup at wolfram.com

```Why did you use SolveAlways? It's meant for a completely different
purpose (identities, not equations!). The best way is to use Reduce:

In:=
eqns = {a + b == c + d, a^2 + b^2 == c^2 + d^2};

In:=
Reduce[eqns,{a,b,c,d}]

Out=
a==c&&b==d||a==d&&b==c

Andrzej Kozlowski
Toyama International University
JAPAN
http://platon.c.u-tokyo.ac.jp/andrzej/

On Friday, March 29, 2002, at 08:13  PM, TheSquaredBun wrote:

> Hi,
>
> I tried to find solutions for a + b = c + d where a^2 + b^2 = c^2 +
> d^2.
>
> In:=
> \!\(\(eqns = {a\  + \ b == c + d, a\^2 + b\^2 == c\^2 + d\^2};\)\)
>
> In:=
> SolveAlways[eqns, {a, b, c, d}]
>
> Out=
> {}
>
> Does anyone have an idea how to handle this problem with mathematica?
>
>
> Roderik,
> TheSquaredBun
>
> ----------------------------------------------
> Top 100 Nederland (gratis aanmelden, direct meer bezoekers)
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>
>
>

```

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