Re: Limit with restrictions
- To: mathgroup at smc.vnet.net
- Subject: [mg34309] Re: [mg34269] Limit with restrictions
- From: Vladimir Bondarenko <vvb at mail.strace.net>
- Date: Tue, 14 May 2002 04:12:30 -0400 (EDT)
- Reply-to: Vladimir Bondarenko <vvb at mail.strace.net>
- Sender: owner-wri-mathgroup at wolfram.com
Dear Hannes,
What I had using the Calculus`Limit` package was
p = m^(-1 + a + b + n)*(a/(a + b + n))^a*((b + n)/
(a + b + n))^(b + n)*(a + b + n);
restrictions = {a > 0, b > 0, n > 0, a + b + n < 1};
<< Calculus`Limit`
Simplify[Limit[p, m -> Infinity],restrictions]
0
My warning is: Please do check the answer carefully using
the (algebraic, geometric etc) context of your problem,
the common sense, at least ;-)
Calculus`Limit` tends to generate wrong answers.
Regards,
Vladimir Bondarenko