RE: How to Properly Use Partition?
- To: mathgroup at smc.vnet.net
- Subject: [mg36732] RE: [mg36725] How to Properly Use Partition?
- From: "DrBob" <drbob at bigfoot.com>
- Date: Sat, 21 Sep 2002 02:21:57 -0400 (EDT)
- Reply-to: <drbob at bigfoot.com>
- Sender: owner-wri-mathgroup at wolfram.com
Maybe this will work for you:
groupDigits[n_String, k_Integer] := Partition[
PadLeft[Characters[n],
k Ceiling[StringLength[n]/k],
"0"],
k]
Bobby Treat
-----Original Message-----
From: flip [mailto:flip_alpha at safebunch.com]
To: mathgroup at smc.vnet.net
Subject: [mg36732] [mg36725] How to Properly Use Partition?
b = 2; r = 4;
n = "10101111"
p = Reverse[Characters[n]]
{"1", "1", "1", "1", "0", "1", "0", "1"}
z = Reverse[Partition[p, r]]
{{"0", "1", "0", "1"}, {"1", "1", "1", "1"}} (* this is okay *)
b = 2; r = 3;
z = Reverse[Partition[p, r]]
{{"1", "0", "1"}, {"1", "1", "1"}} (* this is wrong, want output to be
{{0,1,0},{1,0,1},{1,1,1}}*)
What I want is a function that takes a string as input, parses each
character, partitions that to whatever length I want and Prepends zeros
to
the input as needed to create an appropriate length array.
What is the correct syntax for Partition (or is there a better way?).
Thanks, Flip
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