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Re: Super-Increasing List

  • To: mathgroup at smc.vnet.net
  • Subject: [mg40469] Re: Super-Increasing List
  • From: atelesforos at hotmail.com (Orestis Vantzos)
  • Date: Mon, 7 Apr 2003 04:53:44 -0400 (EDT)
  • References: <b6m04c$efg$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

OrestisSuperIncreasingQ[lst_] := OrderedQ[lst] &&
      Module[{sum = 0}, 
        If[Scan[If[# <= sum, Return[False], sum += #] &, lst] ===
Null, True,
          False]];

The advantage of this function is that it stops checking as long as an
element does not satisfy the super-increasing condition.
Orestis

"flip" <flip_alpha at safebunch.com> wrote in message news:<b6m04c$efg$1 at smc.vnet.net>...
> Hello,
> 
> does a command or module exist which can test a list of values and determine
> if it is a super-increasing list?
> 
> A super-increasing list satifies the conditions:
> 
> a.  the list is in increasing order
> b.  each element of the list is greater than the sum of it's previous
> elements
> 
> Example:
> 
> list = {2, 3, 7, 15, 31}
> 
> So check:
> 
> a.  It is in  increasing order and
> b.   3 > 2, 7 > 3+ 2, 15 > 7 + 3 + 2 and 31 > 15 + 7 + 3 + 2,
> 
> hence the list is super-increasing.
> 
> Thanks for any inputs, Flip
> 
> To email me, remove "_alpha".


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