Re: nonlinear equation
- To: mathgroup at smc.vnet.net
- Subject: [mg40795] Re: nonlinear equation
- From: Raibatak Das <rd54 at cornell.edu>
- Date: Thu, 17 Apr 2003 23:17:11 -0400 (EDT)
- References: <b7irg5$juo$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
pf -
here is an example for some arbitrary values of a, b and x
In[1]:= a=5
Out[1]= 5
In[2]:= b=10
Out[2]= 10
In[3]:= x=1
Out[3]= 1
In[4]:= NSolve[x == a y Log[b] - a y Log[y] + a y, y]
InverseFunction::ifun:
Inverse functions are being used. Values may be lost for multivalued
inverses.
InverseFunction::ifun:
Inverse functions are being used. Values may be lost for multivalued
inverses.
Solve::ifun: Inverse functions are being used by Solve, so some
solutions may
not be found.
Out[4]= {{y -> 0.0292658}, {y -> 26.9821}}
hope this helps.
- rd
pflores at dem.uminho.pt wrote:
>Hello,
>
>Can you help me how to solve a nonlinear equation given by:
>
>x = a*y*ln(b) - a*y*ln(y) + a*y
>
>where a and b are constant parameters.
>I know the inital value of x0 and I want to know the value of y.
>
>Can I use Newton's method? How?
>
>Regards,
>PF
>
>
------------------------------------------------------------------------
* /Raibatak Das / *
Department of Chemistry and Chemical Biology, Cornell University.
Ithaca, NY 14853.
Ph : 1-607-255-6141
email : rd54 at cornell.edu <mailto:rd54 at cornell.edu>