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Re: Dealing with sums

  • To: mathgroup at smc.vnet.net
  • Subject: [mg41000] Re: Dealing with sums
  • From: bobhanlon at aol.com (Bob Hanlon)
  • Date: Mon, 28 Apr 2003 02:30:04 -0400 (EDT)
  • References: <b8g114$pg5$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Unprotect[D];
D[Subscript[a_, m_], 
  Subscript[a_, n_]] := KroneckerDelta[n-m]
Protect[D];

D[Sum[Subscript[a, i], {i, 0, n}], 
  Subscript[a, m]]

UnitStep[m] UnitStep[-m+n]

%//FullSimplify

UnitStep[m,-m+n]

D[Sum[Subscript[a, i], {i, 0, n}], 
  Subscript[a, 3]]

UnitStep[-3+n]


Bob Hanlon

In article <b8g114$pg5$1 at smc.vnet.net>, Stepan Yakovenko <yakovenko at ngs.ru>
wrote:

<< 
Subject:	Dealing with sums
From:		Stepan Yakovenko <yakovenko at ngs.ru>
To: mathgroup at smc.vnet.net
Date:		Sun, 27 Apr 2003 07:31:48 +0000 (UTC)

HI!

  I want to get a derivative in terms of KroneckerDelta function:

  \!\(\[PartialD]\_\(a\_3\)\(\[Sum]\+\(i = 0\)\%N a\_i\)\)

  But I get 0.
  
  Is there a way to do it in Mathematica ?
  

-- 
Best regards,
 Stepan                          mailto:yakovenko at ngs.ru

 >><BR><BR>


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