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Re: ListPlot3D of a Square Array

  • To: mathgroup at smc.vnet.net
  • Subject: [mg43076] Re: ListPlot3D of a Square Array
  • From: bobhanlon at aol.com (Bob Hanlon)
  • Date: Mon, 11 Aug 2003 02:15:55 -0400 (EDT)
  • References: <bh4mbg$po4$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Clear[m];

Array[m, {5,5}]

{{m[1, 1], m[1, 2], m[1, 3], m[1, 4], m[1, 5]}, 
  {m[2, 1], m[2, 2], m[2, 3], m[2, 4], m[2, 5]}, 
  {m[3, 1], m[3, 2], m[3, 3], m[3, 4], m[3, 5]}, 
  {m[4, 1], m[4, 2], m[4, 3], m[4, 4], m[4, 5]}, 
  {m[5, 1], m[5, 2], m[5, 3], m[5, 4], m[5, 5]}}

Standing alone (e.g., without being part of a Set statement), the results of an
Array command are transient.  Note the definition of m:

?m

Global`m

Whether or not there is anything to plot depends on the <fill up m> commands
that you omitted.  Perhaps you intended something like

m=Array[3*#1-5*#2&, {5,5}];

ListPlot3D[m];


Bob Hanlon

In article <bh4mbg$po4$1 at smc.vnet.net>, "Scott Guthery"
<sguthery at mobile-mind.com> wrote:

<< Insight into the following is appreciated:
 
Array[m, {5,5}]
<fill up m>
ListPlot3D[m]
 
ListPlot3D grumps that m is not a rectangular
array larger than 2x2.
 
Looks like it is to me!?!?
  >><BR><BR>


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