Re: a first-time user question
- To: mathgroup at smc.vnet.net
- Subject: [mg39427] Re: [mg39352] a first-time user question
- From: "German Buitrago A." <gerbual at col2.telecom.com.co>
- Date: Fri, 14 Feb 2003 03:24:43 -0500 (EST)
- References: <200302120852.DAA14779@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
As y=x^(2/3) is equivalent to y^3=x^2, you can use:
<< "Graphics`ImplicitPlot`"
ImplicitPlot[y^3 == x^2,
{x, -1, 1}]
Germán Buitrago A.
Manizales, Colombia
----- Original Message -----
From: "Ye Hu" <huye at wharton.upenn.edu>
To: mathgroup at smc.vnet.net
Subject: [mg39427] [mg39352] a first-time user question
> I have a simple (supposedly) question...
>
> I used the following command to draw a plot, but Mathematica could not run
> properly.
>
> Plot[x^(2/3),{x,-1,0}]
>
>
> I know the problem is about calculating (-1)^(1/3) in mathematica.
Although
> (-1)^(1/3) = -1,
> mathematica tries to calculate it numerically and gives complex results
> 0.5+0.8i
> How to solve this problem and restrict the solution to be only real
numbers?
>
> Thanks very much.
>
>
>
- References:
- a first-time user question
- From: "Ye Hu" <huye@wharton.upenn.edu>
- a first-time user question