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Re: Delete cases nested list

  • To: mathgroup at smc.vnet.net
  • Subject: [mg42784] Re: Delete cases nested list
  • From: bobhanlon at aol.com (Bob Hanlon)
  • Date: Fri, 25 Jul 2003 11:54:53 -0400 (EDT)
  • References: <bfqt01$nsu$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

lis3=DeleteCases[lis1,
    _?(Intersection[#, lis2]!={}&)]

or

lis3=DeleteCases[lis1,
    _?(MemberQ[lis2, Last[#]]&)]


Bob Hanlon

In article <bfqt01$nsu$1 at smc.vnet.net>, "The Leddons" <jleddon1 at comcast.net>
wrote:

<< I have 2 lists, lis1 and lis2, I want to compare to each other for the 
purpose of deleting sublists of lis1 that have elements matching those 
in lis2. I tried this:

lis1 = {{2, 3, 4, 5, 6, 7, C1}, {2, 3, 4, 5, 6, 71, B6}, {1, 2, 3, 4, 
5, 6, C11}, {4, 5, 6, 7, 8, 7, C4}, {23, 3, 2, 5, 6, 7, M2}, {2, 3, 9, 
5, 6, 71, B3}};

lis2 = {C11, B6, B3};

lis3 = DeleteCases[lis1, {x_lis2}, {2}]

What I want is:

lis3 = {{2, 3, 4, 5, 6, 7, C1}, {4, 5, 6, 7, 8, 7, C4}, {23, 3, 2, 5, 6, 7,
M2}};

However, this didn't work. Note that I want to delete all cases containing B.


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