Re: plotting of curve
- To: mathgroup at smc.vnet.net
- Subject: [mg42157] Re: plotting of curve
- From: gohtk at rocketmail.com (goh tat kean)
- Date: Sat, 21 Jun 2003 02:49:34 -0400 (EDT)
- References: <bcuiaf$2p9$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Dear Kee,
I am not sure whether I understand your question correctly. What I
think are given as below:
You have an equation of 2*Exp[1/(Wx)]/(587 - x)^2,
I rewrite it as
y = 2*Exp[1/(w x)]/(587 - x)^2
You mentioned w = 5.8 and you want to plot the generated equation as y
against 1/(w x),
w = 5.8;
Create a table comprises of 1/(w x) and y (your equation),
list1 = Table[{1/(w x), y}, {x, 1, 20}];
Plot the values,
p1=ListPlot[list1];
Hope this can help. Good luck!
Regards,
tat kean
ce.choa.phen.kee at philips.com wrote in message news:<bcuiaf$2p9$1 at smc.vnet.net>...
> Hi all,
>
> May I know how can I plot this equation 2*Exp[1/(Wx)]/(587 - x)^2 which I have gotten from
> this function: NonlinearFit[values, (MM * Exp[1/Wx])/(NN-x)^2,
> {x,1/(Wx)},{{MM,5},{NN,600}}]?
>
> I made use of x-values and 1/(Wx) values to fit the data into the desired
> equations. But just have no idea on how to plot the generated equation as y against 1/(Wx).
>
> Given W is 5.8 and the two x in the equation are both using the same
> x-values..
>
> pls guide..
>
> Thanks in advance.
>
> regards,
> kee