MathGroup Archive 2003

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Holes when plotting funtions

  • To: mathgroup at smc.vnet.net
  • Subject: [mg42199] Re: Holes when plotting funtions
  • From: "Kevin J. McCann" <KevinMcCann!kjm at uunet.uu.net>
  • Date: Mon, 23 Jun 2003 05:49:40 -0400 (EDT)
  • References: <bd2vuf$1dn$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Technincally you are almost correct in that your function as it stands is
not defined for x = 0. This is a little different from "not defined around
zero," which implies that it is not defined in some interval around zero.
However,

Limit[f[x],x->0] = 3

So the function has a removable singularity at x = 0. If you amend your
definition so that the function is defined to be 3 at x = 0, and has your
original definition elsewhere, then the function is continuous.

Cheers,

Kevin

"Ashraf El Ansary" <Elansary at btopenworld.com> wrote in message
news:bd2vuf$1dn$1 at smc.vnet.net...
> Hi,
> Is there any way to mathematica to distinguish non-continous equations in
> the 'Plot' function. For example:
> f[x_]:=x(1-Cos[x])/(x-Sin[x])
> Plot[f[x],{x,-20,20},AxesLabel->{x,y},AxesOrigin->{0,0}]
>
> The above example is not defined around zero, but when plotted by
> Mathematica , it looks as if the function is continous. Is there any way
to
> plug a whole in those intervals which are not continous (simillar to those
> depicted in textbooks for step /open/closed intervals]......
>
>
> Cheers.
>
>
> Ashraf
>
>



  • Prev by Date: Re: loading packages
  • Next by Date: Re: Re: Holes when plotting funtions
  • Previous by thread: Re: Holes when plotting funtions
  • Next by thread: Re: Re: Holes when plotting funtions