differences in Solve with -1/2 and -0.5
- To: mathgroup at smc.vnet.net
- Subject: [mg44386] differences in Solve with -1/2 and -0.5
- From: "Kenneth Levasseur" <Kenneth_Levasseur at uml.edu>
- Date: Fri, 7 Nov 2003 05:16:43 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Can anyone give a good reason why there is a difference in the
following? Preferably one that my students will understand.
In[1]:=
Solve[D[x E^(-x/2), x] == 0, x]
Out[1]=
{{x -> 2}}
In[2]:=
Solve[D[x E^(-0.5*x), x] == 0, x]
General::dbyz:Division by zero.
Out[2]=
{}
Ken Levasseur
Math. Sciences
UMass Lowell
- Follow-Ups:
- Re: differences in Solve with -1/2 and -0.5
- From: Andrzej Kozlowski <akoz@mimuw.edu.pl>
- Re: differences in Solve with -1/2 and -0.5