Re: Expansion of an exponential expression
- To: mathgroup at smc.vnet.net
- Subject: [mg47259] Re: Expansion of an exponential expression
- From: drbob at bigfoot.com (Bobby R. Treat)
- Date: Thu, 1 Apr 2004 00:03:59 -0500 (EST)
- References: <c4bdrj$6uu$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Log[((2 + Sqrt[1 + 2*h])^(-1))^(t/h)] // PowerExpand
-((t*Log[2 + Sqrt[1 + 2*h]])/h)
Series[%, {h, 0, 5}]
SeriesData[h, 0,
{-(t*Log[3]), -t/3,
(2*t)/9, (-19*t)/81,
(97*t)/324, (-2059*t)/
4860, (11191*t)/17496},
-1, 6, 1]
Bobby
carlos at colorado.edu (Carlos Felippa) wrote in message news:<c4bdrj$6uu$1 at smc.vnet.net>...
> As a result of some calculations I have
> (a snipet of a more complex expression)
>
> anlog= Log[ ((2 + Sqrt[1 + 2*h])^(-1))^(t/h) ]
>
> I would like to simplify this to
>
> anlog= (t/h) Log[((2 + Sqrt[1 + 2*h])^(-1)) ]
>
> so I can then take the Taylor series in h.
> But FullSimplify[anlog,h>0] doesnt do it.
> Do i need a ComplexityFunction?