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Re: Simply derivative question, Math 5.

  • To: mathgroup at smc.vnet.net
  • Subject: [mg50251] Re: [mg50240] Simply derivative question, Math 5.
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Mon, 23 Aug 2004 06:34:13 -0400 (EDT)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

The input form of the exponential constant is E not e

D[(1 + c*e^t)/(1 - c*e^t),t]//Simplify

(2*c*e^t*Log[e])/(c*e^t - 1)^2

D[(1 + c*E^t)/(1 - c*E^t),t]//Simplify

(2*c*E^t)/(c*E^t - 1)^2


Bob Hanlon

> 
> From: "Ted Kahn" <tedkahn at mindspring.com>
To: mathgroup at smc.vnet.net
> Date: 2004/08/22 Sun AM 12:19:51 EDT
> To: mathgroup at smc.vnet.net
> Subject: [mg50251] [mg50240] Simply derivative question, Math 5.
> 
> Hello- I am trying to take the derivative of the following function:
> 
> (1 + c*e^t)/(1 - c*e^t)
> 
> with respect to t.
> 
> ================
> \!\(Simplify[D[\(1 + c\ e\^t\)\/\(1 - c\ e\^t\), t]]\)
> ============
> 
> The answer I get includes an "extra" Log[e] in the numerator. Am I not  
> using the program correctly or am I not understanding the answer  
> correctly? Other?
> 
> thanks, -ted
> -- 
> 
> 


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