Re: Finding the Fourier transform of discrete functions
- To: mathgroup at smc.vnet.net
- Subject: [mg52661] Re: Finding the Fourier transform of discrete functions
- From: "Jens-Peer Kuska" <kuska at informatik.uni-leipzig.de>
- Date: Tue, 7 Dec 2004 04:09:55 -0500 (EST)
- Organization: Uni Leipzig
- References: <cohi1d$1fh$1@smc.vnet.net> <200412011057.FAA19902@smc.vnet.net> <comgk7$7a2$1@smc.vnet.net> <copa52$pmk$1@smc.vnet.net> <cos0k6$dgj$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Hi, f[x_Integer]]/;1<=x<=12 = Sin@x say that for a integer x in [1,12] the function can be simplifyed to Sin[x], it say *not* that for other arguments the function is indeterminate. The additional definition f[_]:=Indeterminate would do that. Regards Jens "Peter Pein" <petsie at arcor.de> schrieb im Newsbeitrag news:cos0k6$dgj$1 at smc.vnet.net... > Jens-Peer Kuska wrote: >> Hi, >> >> and you think that 1<=x<12 is discret, and not a infinite number >> of continuous values ?? Strange ! >> >> Regards >> Jens >> >> "DrBob" <drbob at bigfoot.com> schrieb im Newsbeitrag >> news:comgk7$7a2$1 at smc.vnet.net... >> >>>>>what is a "discrete function". >>>>>if it is a function, the parameter is continuous and FourierTransform[] >>>>>compute the transformation. >>> >>>A discrete function is a function with a discrete domain. >>> >>>For instance, this is a discrete function on the obvious domain: >>> >>>f[x_Integer]/;1<=x<=12 = Sin@x > *^^^^^^^^* >>>It is NOT the Sin function, for the simple reason that the domain of a >>>function (in math or mathematica) is part of its definition. >>> >>>Bobby >>>.... > > I think, it's his firm conviction that there are only 12 Integers x in > the interval 1<=x<=12. ;-) > > -- > Peter Pein > 10245 Berlin >
- References:
- Re: Finding the Fourier transform of discrete functions
- From: "Jens-Peer Kuska" <kuska@informatik.uni-leipzig.de>
- Re: Finding the Fourier transform of discrete functions