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Re: How to evaluate Exp[I Pi(1+x)]?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg52750] Re: How to evaluate Exp[I Pi(1+x)]?
  • From: nospam nospam <nospam_please at nospam.com>
  • Date: Sat, 11 Dec 2004 05:22:40 -0500 (EST)
  • References: <cpavhd$ivc$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

hello wrote:
> Is there a way to evaluate Exp[I Pi (1+x)]? I am expecting to see the
> result to be:
> 
> -Exp[I Pi x]
> 
> because Exp[I Pi] can be reduced to shorter form.
> 

ComplexExpand[Exp[I Pi (1 + x)]]

Cos[Pi (1 + x)] + I Sin[Pi (1 + x)]

(this is Euler formula)


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