       Re : fullsimplify problem

• To: mathgroup at smc.vnet.net
• Subject: [mg52922] Re : [mg52908] fullsimplify problem
• From: "Jaccard Florian" <Florian.Jaccard at he-arc.ch>
• Date: Fri, 17 Dec 2004 05:18:31 -0500 (EST)
• Sender: owner-wri-mathgroup at wolfram.com

```Why do you consider the output as incorrect?
I'd say it is elementary algebra.
If -a/b^2 == a/b^2 , then 2a/b^2==0 , so a==0 and b!=0   or   b==Infinity
a/b==0  is equivalent!
Don't you think so ?

regards

F.Jaccard

-----Message d'origine-----
De : symbio [mailto:symbio at has.com]
Envoyé : jeudi, 16. décembre 2004 09:41
À : mathgroup at smc.vnet.net
Objet : [mg52908] fullsimplify problem

Given ( - a / b^2) = =  ( + a / b^2), it can be written as (-2 a / b^2), but
when I use FullSimplify on that equation, I get the incorrect result ( a /
b ) = = 0.  How is this possible?

In:=
-a/b^2 == a/b^2
% // FullSimplify
Out=
\!\(\(-\(a\/b\^2\)\) == a\/b\^2\)
Out=
\!\(a\/b == 0\)

In:=
-2a/b^2 == 0 // FullSimplify
Out=
\!\(a\/b == 0\)

```

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