Re: Coefficients of previous result
- To: mathgroup at smc.vnet.net
- Subject: [mg53117] Re: Coefficients of previous result
- From: "Steve Luttrell" <steve_usenet at _removemefirst_luttrell.org.uk>
- Date: Fri, 24 Dec 2004 05:59:04 -0500 (EST)
- References: <cqeglg$l0g$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
expr = (1. + 2.*x + 2.*x^2 + 2.*x^3)/(1. + 2.*x + 2.*x^2) gives (1. + 2.*x + 2.*x^2 + 2.*x^3)/(1. + 2.*x + 2.*x^2) then Rationalize[expr] gives (1 + 2*x + 2*x^2 + 2*x^3)/(1 + 2*x + 2*x^2) Steve Luttrell "Milind Gupta" <milind.gupta at gmail.com> wrote in message news:cqeglg$l0g$1 at smc.vnet.net... > The result of my previous step is something like this: > > expr = 1. + 2. x + 2. x^2 + 2. x^3 > ----------------------------------------- > 1. + 2. x + 2. x^2 > > But I need it to be like this: > > > expr = 1 + 2 x + 2 x^2 + 2 x^3 > ----------------------------------------- > 1 + 2 x + 2 x^2 > > so that I can use it with another function properly. Is there any way > to do that? > > Milind >