Re: Problem with graphics
- To: mathgroup at smc.vnet.net
- Subject: [mg45930] Re: Problem with graphics
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Fri, 30 Jan 2004 04:15:56 -0500 (EST)
- Organization: Universitaet Leipzig
- References: <bvaojg$a0i$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
- Sender: owner-wri-mathgroup at wolfram.com
Hi, when you Plot[] Sqrt[(x^2)^3] it is *not* x^3 it is Abs[x]^3 because Sqrt[x^2] is Abs[x]. If you need the other parts of the Riemann-Surface you should draw it an selet the one you like. Regards Jens Lautaro Vergara wrote: > > Dear people, > > I have found the following problem. I have ploted > > f[x_, y_] := Sqrt[(x^2 + y^2)^3] > > with Plot3D in order to see how it looks. Then I ploted f[x, 0] (which > is x^3) between -1 and 1 and I got a symmetric plot. It seems that > Mathematica plot the function Sqrt[x^6] or (x^2)^(3/2) and evaluate > first the symmetric term (x^6 or x^2)... > Does anyone knows what it happens and how can it be fixed? > > Thanks in advance! > > Lautaro Vergara