Re: Numerical integration inside numerical integration
- To: mathgroup at smc.vnet.net
- Subject: [mg48835] Re: Numerical integration inside numerical integration
- From: Paul Abbott <paul at physics.uwa.edu.au>
- Date: Fri, 18 Jun 2004 02:13:04 -0400 (EDT)
- Organization: The University of Western Australia
- References: <cark1d$r7v$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
In article <cark1d$r7v$1 at smc.vnet.net>, blah12 at mail.com wrote:
> I'm trying to solve numerically an integral like,
>
> A=some_value
> NIntegrate[f[y,u]*Log[1+NIntegrate[g[y,u,s], {s, A, \[Infinity]}]],
> {u, -\[Infinity],\[Infinity]},{y, -\[Infinity],\[Infinity]}]
>
> I know I am doing this wrong as the inner integration fails because
> it doesn't have specific numerical values for y and u.
> I guess Mathematica doesn't perform numerical integrations from the
> outside to the inside (and so passing each time values of y,u to
> the inner integration).
It does not fail. Consider the following example:
g[y_, u_, s_] := Exp[-s] (Exp[u^2 + 2y^2] - 1)
f[y_, u_] := Exp[-(u^2 + y^2)]
For these g and f we can compute the integral in closed form:
Simplify[Log[Integrate[g[y, u, s], {s, 0, Infinity}] + 1],
{u, y} \[Element] Reals]
Integrate[f[y, u] %, {u, -Infinity, Infinity},
{y, -Infinity, Infinity}]
If we use NIntegrate instead of Integrate (your integral with A = 0),
NIntegrate[f[y, u] Log[NIntegrate[g[y, u, s], {s, 0, Infinity}] + 1],
{u, -Infinity, Infinity}, {y, -Infinity, Infinity}]
then, after a couple of NIntegrate::"inum" messages (which arise, as you
suspected, because the inner NIntegrate attempts to evaluate its
argument before the values of u and y are passed to its integrand), we
get the same answer as from the exact computation.
Defining the function
h[y_, u_?NumericQ] := f[y, u] Log[NIntegrate[g[y, u, s],
{s, 0, Infinity}] + 1]
allows one to compute the integral without any error message,
NIntegrate[h[y, u], {u, -Infinity, Infinity}, {y, -Infinity, Infinity}]
because the argument of NIntegrate is now not evaluated unless u is
numeric.
Cheers,
Paul
--
Paul Abbott Phone: +61 8 9380 2734
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