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Re: Counting Runs

  • To: mathgroup at smc.vnet.net
  • Subject: [mg51919] Re: Counting Runs
  • From: "Jens-Peer Kuska" <kuska at informatik.uni-leipzig.de>
  • Date: Fri, 5 Nov 2004 02:17:12 -0500 (EST)
  • Organization: Uni Leipzig
  • References: <cmclmu$i99$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

v={1,1,1,-1,1,1,1,1,1,-1,-1,-1,-1,1}

Length /@ Split[Sort[First /@ Split[v]]]

gives you {2,3}

Regards

  Jens

"Gregory Lypny" <gregory.lypny at videotron.ca> schrieb im Newsbeitrag 
news:cmclmu$i99$1 at smc.vnet.net...
> Looking for an elegant way to count runs to numbers in a series.
> Suppose I have a list of ones and negative ones such as
> v={1,1,1,-1,1,1,1,1,1,-1,-1,-1,-1,1}.
> I'd like to create a function that counts the number of runs of 1s and
> -1s, which in this case is 3 and 2.
>
> Greg
> 



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