Re: Re: finding explicit rule for series
- To: mathgroup at smc.vnet.net
- Subject: [mg52079] Re: [mg52054] Re: [mg52043] finding explicit rule for series
- From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
- Date: Wed, 10 Nov 2004 04:45:17 -0500 (EST)
- References: <200411080813.DAA07931@smc.vnet.net> <200411090636.BAA22765@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
This is easy to prove. Just write n[i]-n[i-1] == 5342543 n[i-1]-n[i-2] == 5342543 ...................... n[2]-n[1] == 5342543 n[1]-n[0] == 5342543 and now add up. Of course you can also prove it by induction. (I failed to notice posting. Maybe someone has already posted the above proof, in which case I apologise for the duplication). Andrzej Kozlowski Chiba, Japan http://www.akikoz.net/~andrzej/ http://www.mimuw.edu.pl/~akoz/ On 9 Nov 2004, at 15:36, DrBob wrote: > *This message was transferred with a trial version of CommuniGate(tm) > Pro* > It turns out that n[i] == 5342543 i + n[0]. > > n[i_?Positive]:=5342543+n[i-1] > n/@Range@5 > 5342543Range@5+n[0] > > {5342543+n[0],10685086+n[0],16027629+n[0],21370172+n[0],26712715+n[0]} > > {5342543+n[0],10685086+n[0],16027629+n[0],21370172+n[0],26712715+n[0]} > > I calculated a few terms both ways and the answers agree. > > Bobby > > On Mon, 8 Nov 2004 03:13:28 -0500 (EST), Uwe Ziegenhagen > <newsgroup at ziegenhagen.info> wrote: > >> Hello, >> >> i have a series of numbers and would like to use Mathematica to find >> the >> explicit algorithm in that way: >> >> n(i)=5342543+n(i-1).... >> >> I already spent some time with the manual, but didn't find anything. >> >> Uwe >> > > > > -- > DrBob at bigfoot.com > www.eclecticdreams.net > >
- References:
- finding explicit rule for series
- From: Uwe Ziegenhagen <newsgroup@ziegenhagen.info>
- Re: finding explicit rule for series
- From: DrBob <drbob@bigfoot.com>
- finding explicit rule for series