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Re: Re: Can't get graph to display when using ImplicitPlot!

  • To: mathgroup at smc.vnet.net
  • Subject: [mg50592] Re: Re: Can't get graph to display when using ImplicitPlot!
  • From: "Steve Luttrell" <steve_usenet at _removemefirst_luttrell.org.uk>
  • Date: Sat, 11 Sep 2004 06:44:58 -0400 (EDT)
  • References: <chmo3n$9us$1@smc.vnet.net> <200409090918.FAA19413@smc.vnet.net> <chro33$4v4$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

You are right of course. I habitually use the full set of arguments (modulo 
options) to ImplicitPlot so I forgot about the simpler form that omitted the 
y-range.  Now I am really confused about what might be wrong, unless (as 
some others have suggested) you evaluated ImplicitPlot  before 
<<Graphics`ImplicitPlot`, but your In and Out numbers tell me otherwise.

Steve Luttrell

"Murray Eisenberg" <murray at math.umass.edu> wrote in message 
news:chro33$4v4$1 at smc.vnet.net...
>A y-range is NOT required for such a use of ImplicitPlot!
>
> Steve Luttrell wrote:
>
>> You omitted the y range.
>>
>> ImplicitPlot[x^2 + 2 y == 3, {x, -2, 2}, {y, -2, 2}]
>>
>> Steve Luttrell
>>
>> "Paul" <paul at selfreferral.com> wrote in message
>> news:chmo3n$9us$1 at smc.vnet.net...
>>
>>>For some reason I cannot get the graph to display when using the
>>>ImplicitPlot function. Everything else seems to be working fine. I can
>>>get a graph is I use Plot for example.
>>>
>>>Here is what I do:
>>>
>>>In[26]:=
>>><< Graphics`ImplicitPlot`
>>>In[31]:=
>>>ImplicitPlot[x^2 + 2 y == 3, {x, -2, 2}]
>>>Out[31]=
>>>ImplicitPlot[x^2 + 2 y == 3, {x, -2, 2}]
>>>
>>>Any ideas?
>>>Paul
>
> -- 
> Murray Eisenberg                     murray at math.umass.edu
> Mathematics & Statistics Dept.
> Lederle Graduate Research Tower      phone 413 549-1020 (H)
> University of Massachusetts                413 545-2859 (W)
> 710 North Pleasant Street            fax   413 545-1801
> Amherst, MA 01003-9305
> 



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