Re: confusion about Thread[]
- To: mathgroup at smc.vnet.net
- Subject: [mg56030] Re: confusion about Thread[]
- From: dh <dh at metrohm.ch>
- Date: Thu, 14 Apr 2005 08:54:22 -0400 (EDT)
- References: <d3ib2v$9pb$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Hi Torsten,
see below
Torsten Coym wrote:
> Hi group,
>
> given three lists
>
> wLst = {w1, w2, w3}
> zLst = {z1, z2, z3}
> cLst = {c1, c2, c3}
>
> with each element representing a boolean value I want to calculate a
> list of the same function applied to the corresponding elements of wLst,
> zLst, cLst respectively. While the expression
>
>
> Thread[Thread[wLst && zLst] || Thread[wLst && cLst] ||
> Thread[zLst && cLst]]
>
>
> {(w1 && z1) || (w1 && c1) || (z1 && c1), (w2 && z2) || (w2 && c2) ||
> (z2 && c2), (w3 && z3) || (w3 && c3) || (z3 && c3)}
>
> does exactly what I want, I wonder why the following approach using a
> pure function with three input arguments and a single call of Thread[]
> does not give the desired result:
>
>
> Thread[((#1 && #2) || (#1 && #3) || (#2 && #3) & )[wLst, zLst, cLst]]
>
> ({w1, w2, w3} && {z1, z2, z3}) || ({w1, w2, w3} && {c1, c2, c3}) ||
> ({z1, z2, z3} && {c1, c2, c3})
You simply forgot the inner Thread:
Thread[(Thread[(#1 && #2)] || Thread[(#1 && #3)] || Thread[(#2 && #3)]
&)[wLst, zLst, cLst]]
SIncerely, Daniel
>
> although
>
> ((#1 && #2) || (#1 && #3) || (#2 && #3) & )[w1, z1, c1]
>
> (w1 && z1) || (w1 && c1) || (z1 && c1)
>
> implements the desired logical expression and
>
>
> Thread[f[wLst, zLst, cLst]]
>
> {f[w1, z1, c1], f[w2, z2, c2], f[w3, z3, c3]}
>
> works the way I expect it.
>
>
> It seems I am a bit disconnected here ...
>
> Torsten
>