Re: arrange lists side by side
- To: mathgroup at smc.vnet.net
- Subject: [mg56584] Re: [mg56538] arrange lists side by side
- From: John Kiehl <john.kiehl at soundtrackny.com>
- Date: Fri, 29 Apr 2005 03:21:27 -0400 (EDT)
- Reply-to: John Kiehl <john.kiehl at soundtrackny.com>
- Sender: owner-wri-mathgroup at wolfram.com
Your problem immediately made me think of MapIndexed[ ] which uses a second parameter (#2) to refer to the position of each element that's being Mapped onto. There's an inelegant detail with subtracting 1 and adding 1, as well as needing Sequence[] to get the bracketing as desired.
On Thursday, April 28, 2005 2:40 AM, marloo3 at mail15.com wrote:
>Hi
>is there a way to spread out a small list over a bigger list recurrently like
>this:
>a={28, 30, 17};
>b={1, 2, 9, 4, 5, 7, 3, 8};
>to give the output:
>{{1,28},{2,30},{9,17},{4,28},{5,30},{7,17},{3,28},{8,30}};
>the number of items in "b" do not neccesary multiples of the number of items
>in "a"
>mark
>
>okay this is my approach
>
>a={28,30,17};
>b={1,2,9,4,5,7,3,8};
>aa={};aa=Table[Join[aa,a],{i,Length[b]/Length[a]}]
>
>Out[]=
>{{28,30,17},{28,30,17}}
>
>frc=Mod[Length[b],Length[a]];
>gg=Flatten[Join[aa,Part[a,{1,frc}]]];
>Transpose[Join[{b},{gg}]]
>
>Out[]=
>{{1,28},{2,30},{9,17},{4,28},{5,30},{7,17},{3,28},{8,30}}
>
>----------------------------------------------------------------------
>
>
>