Re: Product {for p=2 to infinity} (p^2+1)/(p^2-1) version=3.0.2
- To: mathgroup at smc.vnet.net
- Subject: [mg53953] Re: [mg53937] Product {for p=2 to infinity} (p^2+1)/(p^2-1) version=3.0.2
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Sat, 5 Feb 2005 03:15:09 -0500 (EST)
- Reply-to: hanlonr at cox.net
- Sender: owner-wri-mathgroup at wolfram.com
Product[(p^2+1)/(p^2-1),
{p, 2,Infinity}]//FullSimplify
Sinh[Pi]/Pi
%//N
3.67608
Verify result:
ListPlot[Table[{m,Product[(p^2+1)/(p^2-1),
{p, 2,m}]},{m,5,150,5}],
PlotJoined->True];
Table[Product[(p^2+1)/(p^2-1),
{p, 2,m}],{m,5,200,5}] ==
Table[Times@@Table[(p^2+1)/(p^2-1),
{p, 2,m}],{m,5,200,5}]
True
Bob Hanlon
>
> From: seidovzf at yahoo.com (Zak Seidov)
To: mathgroup at smc.vnet.net
> Date: 2005/02/04 Fri AM 04:12:17 EST
> To: mathgroup at smc.vnet.net
> Subject: [mg53953] [mg53937] Product {for p=2 to infinity} (p^2+1)/(p^2-1)
>
> Dear Math gurus,
> I try to copy Math session:
> \!\(FullSimplify[\[Product]\+\(p = 2\)\%\[Infinity]\((\(p\^2 +
> 1\)\/\(p\^2 - \1\))\)]
> n Sinh[\[Pi]]\/\[Pi]\),
> that is,
> Product {for p=2 to infinity} (p^2+1)/(p^2-1)=>
> sinh(pi)/pi=3.67608 -
> is it OK,
> or this should be 3/2?
> Please email me your help:
> seidovzf at yahoo.com
>
> Many thanks,
> Zak
>
>