Re: Re: grphing in Mathematica
- To: mathgroup at smc.vnet.net
- Subject: [mg54438] Re: [mg54374] Re: grphing in Mathematica
- From: Chris Chiasson <chris.chiasson at gmail.com>
- Date: Sun, 20 Feb 2005 00:10:15 -0500 (EST)
- References: <bsire1sg1x3j@legacy> <200502190732.CAA06135@smc.vnet.net>
- Reply-to: Chris Chiasson <chris.chiasson at gmail.com>
- Sender: owner-wri-mathgroup at wolfram.com
Needs["Graphics`ContourPlot3D`"]
ContourPlot3D[x^2 + y^2 + 4z^2 - 1, {x, -1, 1}, {y, -1, 1}, {z, -1, 1},
PlotPoints -> 6, AspectRatio -> 1]
Neato :]
On Sat, 19 Feb 2005 02:32:39 -0500 (EST), highegg <highegg at centrum.cz> wrote:
> On 17 Feb 05 12:08:58 -0500 (EST), Nick wrote:
> >How do I graph the function x^2+y^2+4z^2=1?
> >I am using Mathemetica version 4 and
> >using ContourPlot3D doesn't work.
>
> Mathematica plots implicit curves using ImplicitPlot, however, it's a
> planar version only and as far as I am aware standard packages of Mathematica
> 5.1 implement no 3D version. If you are able to parametrize the curve,
> use ParametricPlot3D. Otherwise you're left to create a suitable
> package yourself.
>
> Jaroslav
>
>
--
Chris Chiasson
Kettering University
Mechanical Engineering
Graduate Student
1 810 265 3161
- References:
- Re: grphing in Mathematica
- From: highegg@centrum.cz (highegg)
- Re: grphing in Mathematica