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Re: Construcing correlation matrix from time-ordered list

  • To: mathgroup at smc.vnet.net
  • Subject: [mg54749] Re: [mg54707] Construcing correlation matrix from time-ordered list
  • From: DrBob <drbob at bigfoot.com>
  • Date: Mon, 28 Feb 2005 03:28:44 -0500 (EST)
  • References: <200502270629.BAA25482@smc.vnet.net>
  • Reply-to: drbob at bigfoot.com
  • Sender: owner-wri-mathgroup at wolfram.com

{{1897, 1, 4}, 40.37`} clearly isn't just "the year, then the value", so I'm assuming each entry is actually {{year, month, day}, value}.

The table you seem to want can't be filled if there's not an equal number of data points for each year, and it's not clear how you're defining rows - based on month and day, maybe?

Even this much may be useful to you:

data={{{1897,1,4},40.37`},{{1897,1,5},40.87`},{{1897,1,6},40.95`},{{1897,1,
       7},40.87`},{{1897,1,8},40.97`},{{1897,1,
       11},40.75`},{{1897,1,12},41.4`},{{1897,1,
       13},41.45`},{{1897,1,14},41.79`},{{1897,1,15},42.27`},{{
     1897,1,18},42.76`},{{1897,1,19},43.25`},{{
     1897,1,20},42.78`},{{1897,1,21},42.52`},{{1897,1,22},42.42`}};
Transpose@{data[[All,1,1]],data[[All,2]]}

{{1897,40.37},{1897,40.87},{1897,40.95},{1897,40.87},{
   1897,40.97},{1897,40.75},{
   1897,41.4},{1897,41.45},{1897,41.79},{1897,42.27},{1897,42.76},{
     1897,43.25},{1897,42.78},{1897,42.52},{1897,42.42}}

Beyond that, here's an approach that counts entries in each year and defines rows from one to the maximum count.

(inputs:)
Clear[f, count]
count[_] = 0;
Scan[(f[#[[1, 1]], count[#[[1, 1]]]++] = #[[2]]) &, data]
{maxYear, minYear} = Through[{Max, Min}@data[[All, 1, 1]]]
maxRows = Max[count /@ Range[minYear, maxYear]]
TableForm[Table[f[year,
   row], {row, 0, maxRows - 1},
  {year, minYear, maxYear}], TableHeadings ->
     {None, Range[minYear, maxYear]}]

(outputs:)
{1897,1897}
15
TableForm[{{1897}, {40.37},
    {40.87}, {40.95}, {40.87},
    {40.97}, {40.75}, {41.4},
    {41.45}, {41.79}, {42.27},
    {42.76}, {43.25}, {42.78},
    {42.52}, {42.42}},
   TableHeadings ->
    {None, {1897}}]

Bobby

On Sun, 27 Feb 2005 01:29:57 -0500 (EST), Adam Getchell <agetchell at physics.ucdavis.edu> wrote:

> Hello all,
>
> I have time series data (a lot of it) in a format like:
>
> {{{1897,1,4},40.37`},{{1897,1,5},40.87`},{{1897,1,6},40.95`},{{1897,1,7},
>     40.87`},{{1897,1,8},40.97`},{{1897,1,11},40.75`},{{1897,1,12},
>     41.4`},{{1897,1,13},41.45`},{{1897,1,14},41.79`},{{1897,1,15},
>     42.27`},{{1897,1,18},42.76`},{{1897,1,19},43.25`},{{1897,1,20},
>     42.78`},{{1897,1,21},42.52`},{{1897,1,22},42.42`}}
>
> ie the year, then the value, for 100+ years.
>
> I'd like to construct a correlation matrix so that year values become
> columns, e.g.
>
> 1897      1898
> ==========
> Value1     Value 1
> Value 2     Value 2
> ...
>
>  From my long list of {{{date1},value1},{{date2},value2}}
>
> But I'm not yet sure how to proceed. I'm looking at Cases or Select to
> apply a function for each year range that will pick out that column.
>
> Any pointers appreciated.
>
> --Adam Getchell
>
>
>
>
>



-- 
DrBob at bigfoot.com
www.eclecticdreams.net


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