Re: Re: how to find n in expression x^n using a pattern?
- To: mathgroup at smc.vnet.net
- Subject: [mg58505] Re: [mg58487] Re: [mg58426] how to find n in expression x^n using a pattern?
- From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
- Date: Tue, 5 Jul 2005 01:57:44 -0400 (EDT)
- References: <200507020806.EAA01589@smc.vnet.net> <200507040624.CAA05758@smc.vnet.net> <26A87A3E-2A81-483F-B880-FD4E30020592@gmail.com>
- Sender: owner-wri-mathgroup at wolfram.com
On 4 Jul 2005, at 18:32, Andrzej Kozlowski wrote:
>
> Timing[Cases[p[x], x^(n_.) -> n, {1}]]
>
>
> {0.0005019999999973379*Second, {5}}
>
> (as I wrote in my first response, giving the correct level
> specification is important).
>
On the other hand, the default level specification for Cases is, of
course, {1}...
Andrzej Kozlowski
- References:
- how to find n in expression x^n using a pattern?
- From: "steve" <nma124@hotmail.com>
- Re: how to find n in expression x^n using a pattern?
- From: Pratik Desai <pdesai1@umbc.edu>
- how to find n in expression x^n using a pattern?