Re: Extract Coefficients of Fourier Series
- To: mathgroup at smc.vnet.net
- Subject: [mg58824] Re: Extract Coefficients of Fourier Series
- From: dh <dh at metrohm.ch>
- Date: Wed, 20 Jul 2005 00:29:22 -0400 (EDT)
- References: <dbie2e$brj$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Hello,
squaring and adding the coefficients can be done by pattern matching.
Assume that fs is your fourier series. Then
fs/. {a_Real Sin[_] :> a^2 , a_Real Cos[_] :> a^2 , a_Real -> a^2}
will replace Sin/Cos terms by the square of their coefficients and
finally take care of the zero term. Therefore, the sequence of the
replacement rules is important here. Addition is done automatically by
Mathematica.
sincerely, Daniel
mchangun at gmail.com wrote:
> Hi All,
>
> I have a set of points which have I fitted to a fourier serires with
> the TrigFit function. This gives me a fourier series. What I want is
> to extract all the coefficients of the series, square them, then sum
> them. How do I this (more specifically, the extraction step?
>
> Thanks in advanced.
>