Re: Controlled evaluation of functions
- To: mathgroup at smc.vnet.net
- Subject: [mg56806] Re: [mg56763] Controlled evaluation of functions
- From: "David Park" <djmp at earthlink.net>
- Date: Fri, 6 May 2005 03:00:40 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Brett,
The reason Sin doesn't further evaluate is that you have exact expressions
and Mathematica knows no further rules for it. But make i in your Table an
approximate number and Sin will evaluate and behave just like your k.
So if you don't want k to evaluate, don't give it a definition! Or rather,
make it a rule and then use the rule when you want evaluation. And in
general, if you want controlled evaluation use rules instead of definitions.
krule = k -> (#^2 &);
f[i_, x_] := k[i x]
g[x_] = Table[f[i, x], {i, 3}]
{k[x], k[2 x], k[3 x]}
{3, 0, 1}.g[y]
% /. krule
3 k[y] + k[3 y]
12*y^2
David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/
From: Brett Patterson [mailto:muckle.moose at gmail.com]
To: mathgroup at smc.vnet.net
Consider the following behaviour:
In[1]:= f[i_, x_] := Sin[i x]
In[2]:= g[x_] = Table[f[i, x], {i, 3}]
Out[2]= {Sin[x], Sin[2 x], Sin[3 x]}
In[3]:= {3, 0, 1} . g[y]
Out[3]= 3 Sin[y] + Sin[3 y]
This is what I want to do, but using my own function instead of Sin.
However, this is the result:
In[4]:= k[x_] := x^2 (* This is my alternative to Sin *)
In[5]:= f[i_, x_] := k[i x]
In[6]:= g[x_] = Table[f[i, x], {i, 3}]
Out[6]= {x^2, 4 x^2, 9 x^2} (* I want {k[x], k[2 x], k[3 x]} *)
In[7]:= {3, 0, 1} . g[y]
Out[7]= 12 y^2 (* I want 3 k[y] + k[3 y] *)
How can I get the function k to behave like Sin, so that it is not
evaluated?
Note that in my real application, k is a lot more complex and has
conditions on its arguments, etc.
Thanks!
Brett Patterson