Re: Recursion
- To: mathgroup at smc.vnet.net
- Subject: [mg62300] Re: [mg62274] Recursion
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Sat, 19 Nov 2005 23:18:27 -0500 (EST)
- Reply-to: hanlonr at cox.net
- Sender: owner-wri-mathgroup at wolfram.com
Clear[x]; x[1] = x1; x[t_Integer?Positive] := x[t] = a*x[t - 1](1 - x[t - 1]); Bob Hanlon > > From: JikaiRF at aol.com To: mathgroup at smc.vnet.net > Date: 2005/11/19 Sat AM 05:53:56 EST > Subject: [mg62300] [mg62274] Recursion > > Dear Sirs, > > I would like to obtain trajectories with respect to x, from the following > relationship: > > > > x(t+1)=a x(t)(1-x(t)) > > > > Here, a means a constant with a constraint, 1 < a < 4, t a positive integer > and x a variable. > I know this difference equation cannot be solved by mathematics directly, > because it is not linear. > So, I would like to follow a numerical series in terms of x, and I need to > know how to program Mathematica for this. > > I look forward to your response. > > > > Sincerely, > > Fujio Takata. > >