MathGroup Archive 2005

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: ShowGraphArray

  • To: mathgroup at smc.vnet.net
  • Subject: [mg61784] Re: [mg61766] ShowGraphArray
  • From: <bsyehuda at gmail.com>
  • Date: Sun, 30 Oct 2005 00:43:14 -0400 (EDT)
  • References: <200510290532.BAA24393@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,
Use SetGraphOptions.
evaluete the following small program to see how it works
<< DiscreteMath`Combinatorica`
ShowGraphArray[
Table[SetGraphOptions[CompleteGraph[i],
VertexNumber -> If[EvenQ[i], True, False]], {i, 2, 6}]]
yehuda

On 10/29/05, leigh pascoe <leigh at cephb.fr> wrote:
>
> Dear Mathgroup,
>
> The command
>
> ShowGraphArray[{g1,g2,g3},VertexNumber\[Rule]True]
>
> will display an array of 3 graphic objects with the option specified.
>
> Is it possible to display the 3 graphs, each with different options? If
> so what is the syntax?
>
> A related question would be, how can I determine the available options
> for a given command? (Options[expr] only gives those that have already
> been set.)
>
> Thanks
>
> LP
>
>


  • Prev by Date: Re: graphing x^2+4 on x, y, and i
  • Next by Date: Default argument and conditional pattern question
  • Previous by thread: ShowGraphArray
  • Next by thread: GreaterEqual[x,1] shows up as Greater[x,1]