Re: Solving integrals
- To: mathgroup at smc.vnet.net
- Subject: [mg68685] Re: Solving integrals
- From: Jens Benecke <jens-news at spamfreemail.de>
- Date: Wed, 16 Aug 2006 03:36:16 -0400 (EDT)
- References: <ebhi41$11p$1@smc.vnet.net> <ebpm4o$p9i$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Jens Benecke wrote:
> sorry, this post apparently got mangled ("²" aka "^2" wasn't recognized).
> Here is the integral again:
>
> f := int ( cos(x) / sqrt[ A*A*sin(x/2)*sin(x/2) + (Bx)^2] dx, x=0..N*2*pi
>
> where N==(int)0..20, and A and B are small fixed values (around
> 0.0001..0.05).
Hello everybody,
since I've been told by email a number of times:
yes, I know this integral has a singularity. However, it represents a
physical measure (so it must exist), and a simpler form (without the (Bx)^2
in the denominator) can be and has been solved via conversion to Elliptic
Integrals.
I'm just at a los as how to split this one up.
Please help me a bit :)
--
Jens Benecke