Re: Trigonometric form of complex numbers
- To: mathgroup at smc.vnet.net
- Subject: [mg64196] Re: [mg64158] Trigonometric form of complex numbers
- From: Pratik Desai <pdesai1 at umbc.edu>
- Date: Sun, 5 Feb 2006 04:44:50 -0500 (EST)
- References: <200602030009.TAA10215@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
ivan.svaljek at gmail.com wrote:
>Is there a way to force mathematica to output complex numbers in
>trigonometric form (I guess you call it Phasor).
>Can it return all 3 roots of a complex number in such a form ?
>
>Thanks.
>
>
>
Perhaps something like this (using Phasors)
Clear[z,PolarForm]
PolarForm[u_] :=
Module[{z=u,mod,arg},ToString[Abs[z]]<>"â? "<>ToString[ArcTan[Re[z],Im[z]]]<>"°"]
ls = x /. Solve[x^3 == I, x]//N;
PolarForm /@ ls
Out[88]=
{1.â? -1.5708°,1.â? 0.523599°,1.â? 2.61799°}
Out[89]=
{0.\[InvisibleSpace]-1. \[ImaginaryI],0.866025\[InvisibleSpace]+0.5 \
\[ImaginaryI],-0.866025+0.5 \[ImaginaryI]}
I hacked some code from Andrzej :-)
Hope this helps
Pratik
- References:
- Trigonometric form of complex numbers
- From: ivan.svaljek@gmail.com
- Trigonometric form of complex numbers