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Re: Can anybody help?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg63525] Re: [mg63519] Can anybody help?
  • From: Adriano Pascoletti <pascolet at dimi.uniud.it>
  • Date: Tue, 3 Jan 2006 05:24:41 -0500 (EST)
  • References: <200601030626.BAA26066@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

In[1]:=
v1={1,2,3,4,5,6,7,8,9};
v2={10,11,12,22,32,42,53,63,73};v3={3,5,8};

In[3]:=
Flatten[Position[v1,#]]&/@v3

Out[3]=
{{3},{5},{8}}

In[4]:=
Extract[v2,%]

Out[4]=
{12,32,63}

Adriano Pascoletti

Il giorno 3 gen 2006, alle ore 07:26, Kent Holing ha scritto:

> I have three vecors containg: v1, v2 and v3.
> v1 and v2 has the same length. v3 is shorter than v1.
> All elements of v3 is an element of v1.
> Need to have the corresponding v2 values corresponding to the v3 (=  
> v1) value.
> Know that the elements of v1 and v3 are different. The elements of  
> v2 do not need to different.
> Ex:
> v1={1,2,3,4,5,6,7,8,9}
> v2={10,11,12,22,32,42,53,63,73}
> v3={3,5,8}
> The corresponding v2 values are {11,32,63}
> It easy to write straightforward code to do this.
> But is it really a very elegant/short way (one-liner?) of doing  
> this in Mathematica?
> Kent Holing
>


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